Let is a complete lattice. Let .
I will call weak partitioning of a set such that
I will call strong partitioning of a set such that
Question: Do exist complete lattices for which weak partitioning and strong partitioning are not the same?
If this conjecture (that it is the same for arbitrary complete lattices) is indeed false for arbitrary complete lattices, we must find the cases when it is true. (I strongly suspect that it is true for distributive complete lattices.)